Question

Rules of Logarithms: Can someone explain how to do:
1) e^(2(ln)(x))
2) e^(-lnx)

I know the rules I just don't understand how they apply..
thanks!

Answer 1

the "rule" here is that
e^ln(k) = k

so e^(2lnx)
= e^ln(x^2)
= x^2

and
2) e^(-lnx)
= e^ln(x^-1)
= x^-1
or 1/x

Answer 2

This is not the trigonometry I studied in high school