Asked by Joshua

Suppose you are given the arithmetic sequence 3,6,9,...,99.What is the sum of the terms of this sequence?
Answered by Steve
since the difference is 3, there are (99-3)/3 + 1 = 33 terms

S33 = 33/2 (3+99)
Answered by alexis
Suppose you are given the arithmetic sequence 3,6,9,...,99 . What is the sum of the terms of this sequence?
Answered by Littlegod
The formula of an arithmetic sequence is n(a+z)/2 where a is the first term of the sequence and z is the last term of the sequence. n is the number of terms in a sequence. So in this problem, there would be (99-3)/3 + 1 terms. Which is 33. the first term is 3 and the last term is 99 meaning it would be 3 + 99. then plug the numbers in we would get 33(3+99)/2. which is 33(102)/2 which simplifies to 33(51). 33 x 51 is 1683. So 1683 would be our answer.
Answered by Meow
Very gooooooood