Asked by zhaina
The sum of the 3 terms in arithmetic sequence is 39.if these numbers is increased by 1,5 and 12 respectively the numbers would be in geometric progression. find the second term of the geometric progression?
Answers
Answered by
Steve
3/2 (2a+2d) = 39
(a+d+5)/(a+1) = (a+2d+12)/(a+d+5)
a=11, d=2
AP: 11,13,15
GP: 12,18,27
a=26, d= -13
AP: 26, 13, 0
GP: 27,18,12
(a+d+5)/(a+1) = (a+2d+12)/(a+d+5)
a=11, d=2
AP: 11,13,15
GP: 12,18,27
a=26, d= -13
AP: 26, 13, 0
GP: 27,18,12
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