Asked by zhaina
                The sum of the 3 terms in arithmetic sequence is 39.if these numbers is increased by 1,5 and 12 respectively the numbers would be in geometric progression. find the second term of the geometric progression?
            
            
        Answers
                    Answered by
            Steve
            
    3/2 (2a+2d) = 39
(a+d+5)/(a+1) = (a+2d+12)/(a+d+5)
a=11, d=2
AP: 11,13,15
GP: 12,18,27
a=26, d= -13
AP: 26, 13, 0
GP: 27,18,12
    
(a+d+5)/(a+1) = (a+2d+12)/(a+d+5)
a=11, d=2
AP: 11,13,15
GP: 12,18,27
a=26, d= -13
AP: 26, 13, 0
GP: 27,18,12
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