Asked by Hari bhatta

If ABCDEF is a regular hexagon then prove that ab+ac+ad+ea+fa=4ab
Answered by bobpursley
I assume you mistyped the problem, it meant: ab+ac+ad+ea+fa=4ab where each quantity is a VECTOR.
first, note AB+BC=AC and
AD=AB+BC+CD and
EA (note direction, from E to A)=-(AB+BC+CD+DE) and
FA=-(EF+AE)
Does this help?
Answered by dhan bhandari
in a regular hexagone ABCDEF prove that AB + AC + AD + EA +FA = 4AB
Answered by Vectors
In hexagon ABCDEF prove that AB + AC + AD + EA + FA = 4AB
Answered by Bijay Thakur
If ABCDEF is a regular hexagon then Prove that:
AB+AC+AD+EA+FA=4AB
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