Asked by Sindhuja
In a regular hexagon ABCDEF prove that AB bar+AC bar +AD bar+AE bar+AF bar =6AO bar
Answers
Answered by
Steve
by symmetry, it is clear that
AB+AF = k1*AO
AC+AE = k2*AO
AD = 2AO
Now you should be able to show that k1+k2 = 4
AB+AF = k1*AO
AC+AE = k2*AO
AD = 2AO
Now you should be able to show that k1+k2 = 4
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