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Asked by Sindhuja

In a regular hexagon ABCDEF prove that AB bar+AC bar +AD bar+AE bar+AF bar =6AO bar
9 years ago

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Answered by Steve
by symmetry, it is clear that

AB+AF = k1*AO
AC+AE = k2*AO
AD = 2AO

Now you should be able to show that k1+k2 = 4
9 years ago
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In a regular hexagon ABCDEF prove that AB bar+AC bar +AD bar+AE bar+AF bar =6AO bar

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