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Asked by sankalpa

ABCDEF is a regular hexagon.if AB=a BC=b,express AC ,AD, AND AE In terms of a and b. Also prove that AB +BC+ CD+ DE +EF +FA=0
8 years ago

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Answered by Steve
AC = AB+BC = a+b
and so on.

Of course they sum to zero, since that is a closed path.
8 years ago
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ABCDEF is a regular hexagon.if AB=a BC=b,express AC ,AD, AND AE In terms of a and b. Also prove that AB +BC+ CD+ DE +EF +FA=0

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