Question

A 1mm cross section of copper wire is isolated. The charge that flows through
the cross section is
Q t = 4t^2 + 5
How much current flows through the wire in 6 seconds?
I think you might mean:

Q(t) = 4 t^2 + 5

Q(6) = 4(6)^2 + 5
= 4 * 36 + 5
149A
Q(t)=4t^2+5
dQ/dt= 8t
t=6
8*6=48
I= 48A

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