Asked by Prince
Potassium chlorate is 75% pure 48 gram of oxygen would be produced from how much potassium chlorate
Answers
Answered by
bobpursley
2KClO3 >> 2KCl +3O2
so one gets three moles of O2 for each two moles of the chlorate.
moles of O2=48/32=1.5
so we multiply that by the mole ratio: 1.5*2/3 to get the moles of the chlorate; but it is not pure, so
moles of impure chorate= 1/.75 * 1.5*2/3=4*3*2/3*3*4= 1.3333 moles
mass of that is 1.333*123 grams
so one gets three moles of O2 for each two moles of the chlorate.
moles of O2=48/32=1.5
so we multiply that by the mole ratio: 1.5*2/3 to get the moles of the chlorate; but it is not pure, so
moles of impure chorate= 1/.75 * 1.5*2/3=4*3*2/3*3*4= 1.3333 moles
mass of that is 1.333*123 grams
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.