Question

Potassium chlorate decomposes according to the following equation:
2KCIO3(s)= 2KCl(s) + 3O2(g)

what volume of a gas can be produced by the decomposition of 12.6g of potassium chlorate measured under the following conditions?

a) at STP
b) at SATP

Answer 1

mols KClO3 = grams/molar mass = ?
For every 2 mols KClO3 you get 3 mol O2.
1 mol O2 @ STP occupies 22.4 L so ? mols will give ......
1 mol O2 @ SATP occup;ies 24.5 L so ? mols will give .....

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