Question

how do I find the intercept for x^2+(y-4)^2=0

Answer 1

typo for x^2+(y-4)^2=16

Answer 2

That makes more sense. A circle of zero radius is hard to see.
circle center at x = 0 , y = 4
circle radius = sqrt 16 = 4
so it just grazes the x axis at x = 0
it crosses the y axis at x =0 and , y = 0 and y = 8

Answer 3

how does y=8 do you know?

Answer 4

when x=0, (y-4)^2=16
So, y-4 = ±4
y = 4±4
y=0,8