Question

Find the x-intercept of the equation below. You must show ALL work to earn full credit.

8x+4y=16

Answer 1

this time find the y

Answer 2

To find the x-intercept of the equation \(8x + 4y = 16\), we need to determine the value of \(x\) when \(y = 0\).

Here are the steps:

1. **Substitute \(y = 0\) into the equation:**
\[
8x + 4(0) = 16
\]

2. **Simplify the equation:**
\[
8x + 0 = 16
\]
\[
8x = 16
\]

3. **Solve for \(x\):**
\[
x = \frac{16}{8}
\]
\[
x = 2
\]

The x-intercept is therefore at the point \((2, 0)\).

To summarize, the x-intercept of the equation \(8x + 4y = 16\) is:
\[
\boxed{2}
\]

Answer 3

To find the y-intercept of the equation \(8x + 4y = 16\), we need to determine the value of \(y\) when \(x = 0\).

Here are the steps:

1. **Substitute \(x = 0\) into the equation:**
\[
8(0) + 4y = 16
\]

2. **Simplify the equation:**
\[
0 + 4y = 16
\]
\[
4y = 16
\]

3. **Solve for \(y\):**
\[
y = \frac{16}{4}
\]
\[
y = 4
\]

The y-intercept is therefore at the point \((0, 4)\).

To summarize, the y-intercept of the equation \(8x + 4y = 16\) is:
\[
\boxed{4}
\]