find x-intercept
-0.01x^2+0.7x+6.1
3 answers
check your typing, to find the x-intercept I expected to see an equation in x and y.
find x intercept;
y=-0.01x^2+0.7x+6.1
y=-0.01x^2+0.7x+6.1
x-intercept occurs when y = 0, thus substitute zero value to y:
0 = -0.01x^2 + 0.7x + 6.1
since this is not factorable, use the quadratic formula:
x = [-b +- sqrt(b^2 - 4*a*c)]/(2*a)
note: +- is plus or minus
where a = -0.01, b = 0.7 and c = 6.1
substitute these values and solve for x.
0 = -0.01x^2 + 0.7x + 6.1
since this is not factorable, use the quadratic formula:
x = [-b +- sqrt(b^2 - 4*a*c)]/(2*a)
note: +- is plus or minus
where a = -0.01, b = 0.7 and c = 6.1
substitute these values and solve for x.
7 answers