Asked by Paige
Mass of metal=45.00 grams
Initial temp= 20.0 degrees Celcius
Final temp= 87.0 degrees Celcius
4.184 J/g-specific heat of H2O
The metal was heated up from initial temp to final temp. What would be the metal's highest temperature?
The specific heat of the metal was calculated to be 7.93x10^-1 J/g*degC
Initial temp= 20.0 degrees Celcius
Final temp= 87.0 degrees Celcius
4.184 J/g-specific heat of H2O
The metal was heated up from initial temp to final temp. What would be the metal's highest temperature?
The specific heat of the metal was calculated to be 7.93x10^-1 J/g*degC
Answers
Answered by
paige
Also, another question I have is about enthalpy.
1. Calculate the standard enthalpy change for reaction at 25 deg C. Standard enthalpy formations of
Mg(OH)2(s) +2HCl(g) right arrow MgCl2(s) +2H2O (g)
What is the enthalpy of the rxn in kJ?
I'm calculating everything and got -385 . When I entered the answer it was wrong, so I'm unsure of where I went wrong.
Mg(OH)2(s)=-924.5
HCl(g)=-92.3
MgCl2=-641.3
H2O=-241.8
1. Calculate the standard enthalpy change for reaction at 25 deg C. Standard enthalpy formations of
Mg(OH)2(s) +2HCl(g) right arrow MgCl2(s) +2H2O (g)
What is the enthalpy of the rxn in kJ?
I'm calculating everything and got -385 . When I entered the answer it was wrong, so I'm unsure of where I went wrong.
Mg(OH)2(s)=-924.5
HCl(g)=-92.3
MgCl2=-641.3
H2O=-241.8
Answered by
DrBob222
Your post is not well organized. I assume those temperatures at the top are Tinitial and Tfinal for H2O and not the meal.
[mass metal x specific heat metal x (Tfinal-Tinitial)] + [mass H2O x specific heat H2O x (Tfinal-Tinitial)] = 0
#2.
dS0 = (n*dSo products) - (n*dSo reactants)
Substitute and solve. Post your work if you want us to find the error.
[mass metal x specific heat metal x (Tfinal-Tinitial)] + [mass H2O x specific heat H2O x (Tfinal-Tinitial)] = 0
#2.
dS0 = (n*dSo products) - (n*dSo reactants)
Substitute and solve. Post your work if you want us to find the error.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.