Asked by Anonymous

When 72 grams of a metal at 97.0oC is added to 100.0 grams of water at 25oC, the final temperature is 29.1oC. What is the specific heat capacity (in J/g.oC) of the metal?
Answered by DrBob222
[mass metal x specific heat metal x (Tfinal-Tinitial)] + [mass H2O x specific heat H2O x (Tfinal-Tinitial)] = 0
Substitute the numbers and solve for specific heat metal.
Answered by Hen
Sjs
Answered by Summer
AW C = 12 g/mol ; AW O = 16 g/mol
Answer
HATDOG
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