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lim
x---> -infinity (-3x+1)/ [radical(x^2 + x)]
x---> -infinity (-3x+1)/ [radical(x^2 + x)]
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Answered by
Reiny
getting a "feel" for the numbers
as x ---> ∞ , √)x^2 + x) ----> 0
so as x ---> ∞, Lim (-3x+1)/√(x^2 + x)
= lim (-3x+1)/x
= -3
as x ---> ∞ , √)x^2 + x) ----> 0
so as x ---> ∞, Lim (-3x+1)/√(x^2 + x)
= lim (-3x+1)/x
= -3
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