Asked by Dave
a sum to infinity which is three times the first term. find the first term
Answers
Answered by
Reiny
a/(1-r) = 3a
divide by a
1/(1-r) = 3
1 = 3 - 3r
3r = 2
r = 2/3
plug in r = 2/3
a/(1 - 2/3) = 3a
a/(1/3) = 3a
3a = 3a , which is a true statement,
so "a" can be anything.
But in a GP, the first term cannot be zero
so the first term can be any real number except zero.
divide by a
1/(1-r) = 3
1 = 3 - 3r
3r = 2
r = 2/3
plug in r = 2/3
a/(1 - 2/3) = 3a
a/(1/3) = 3a
3a = 3a , which is a true statement,
so "a" can be anything.
But in a GP, the first term cannot be zero
so the first term can be any real number except zero.
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