Asked by kud
                A rectangular container measures 4m by 3m by 500cm. The container is completely filled with 0. 5 long cubic packets. How many such packets are needed to filled 3/4 of the container?
V = lwh
= 3(4)(5)
= 60
            
            
        V = lwh
= 3(4)(5)
= 60
Answers
                    Answered by
            Emily
            
    Volume divided by the 0.5 gives packets needed to fill the container
60/0.5 = 120 (packets neededto fill entire container)
120 x (3/4) = 90 (packets needed to fill 3/4 of the container)
I think this is correct!
    
60/0.5 = 120 (packets neededto fill entire container)
120 x (3/4) = 90 (packets needed to fill 3/4 of the container)
I think this is correct!
                    Answered by
            Reiny
            
    correct to say the container contains 60 m^3
You are missing the units on the cubic packets, are their sides .5 m each ?
Then there will be 8by6by10 or 480 such packets
(8 along the length, 6 along the width, 48 on the base, and then 10 layers high)
3/4 of 480 = 360
    
You are missing the units on the cubic packets, are their sides .5 m each ?
Then there will be 8by6by10 or 480 such packets
(8 along the length, 6 along the width, 48 on the base, and then 10 layers high)
3/4 of 480 = 360
                    Answered by
            JARED MOGIRE
            
    total no.of packets will be( 5/0.5*4/0.5*3/0.5)= 480 pcs
then 3/4 of 480= 360 packets.
    
then 3/4 of 480= 360 packets.
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