Asked by TayB
A rectangular storage container with an open top is to have a volume of 10 m3. The length of the base is twice the width. Material for the base is thicker and costs $13 per square meter and the material for the sides costs $10 per square meter. Find the cost of the materials for the cheapest such container. Round to the nearest cent.
Answers
Answered by
Steve
the base has area 2w^2
The volume is 10, so the height h=5/w^2
So, the cost is
13(2w^2) + 10(wh + 2wh)
= 26w^2 + 10w(3h)
= 26w^2 + 10w(5/w^2)
= 26w^2 + 50/w
The volume is 10, so the height h=5/w^2
So, the cost is
13(2w^2) + 10(wh + 2wh)
= 26w^2 + 10w(3h)
= 26w^2 + 10w(5/w^2)
= 26w^2 + 50/w
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