Asked by Ally
a rectangular storage area is to be constructed along the sides of a tall building. A security fence is required along the three remaining sides of the area. What is the maximum area that can be enclosed with 1000m fencing?
Answers
Answered by
Steve
500x250
Answered by
Ally
@ Steve I don't completely understand I want to knowhow we got to that answer/
Answered by
Steve
well, draw a diagram. If the width is x, then the length is 1000-2x. So, the area is
a = x(1000-2x) = 1000x-2x^2
da/dx = 1000-4x
da/dx=0 when x=250
As is usual, you will find that for maximum area, the fencing is divided equally among the widths and lengths. In this case, that means 500 ft each.
2 widths of 250' each, and 1 length of 500.
Naturally, for a 4-sided enclosure, that just means a square.
a = x(1000-2x) = 1000x-2x^2
da/dx = 1000-4x
da/dx=0 when x=250
As is usual, you will find that for maximum area, the fencing is divided equally among the widths and lengths. In this case, that means 500 ft each.
2 widths of 250' each, and 1 length of 500.
Naturally, for a 4-sided enclosure, that just means a square.
Answered by
Ally
Ok thanks I don't quite get it but I will follow your steps and Draw the diagram :)
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