Asked by Isabel
Submarine is traveling parallel to the surface of the water 492 feet below the surface. The submarine begins a constant I sent to the surface so that it will emerge on the surface after traveling 3974 feet from the point of its initial ascent? What horizontal distance did the submarine travel during its dissent?
Answers
Answered by
Steve
√(3974^2-492^2) ≈ 3943 ft
love your creative spelling ... not!
love your creative spelling ... not!
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.