Asked by Isabel

Submarine is traveling parallel to the surface of the water 492 feet below the surface. The submarine begins a constant I sent to the surface so that it will emerge on the surface after traveling 3974 feet from the point of its initial ascent? What horizontal distance did the submarine travel during its dissent?

Answers

Answered by Steve
√(3974^2-492^2) ≈ 3943 ft

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