Asked by Chopsticks
                Use the experimental molar mass to determine the molecular formula for compounds having the following analyses.
A.
41.39% carbon, 3.47% hydrogen, 55.14% Oxygen; experimental molar mass 116.07
I got C4H4O4 as the molecular formula.
Can someone check this for me?
            
        A.
41.39% carbon, 3.47% hydrogen, 55.14% Oxygen; experimental molar mass 116.07
I got C4H4O4 as the molecular formula.
Can someone check this for me?
Answers
                    Answered by
            bobpursley
            
    Assume 116.07grams (I didn't check that)
carbon percent= 4*12/116= check
O percent= 4*16/116= it checks.
Notice how I checked it by working from the formula you proposed back to the original percents.
    
carbon percent= 4*12/116= check
O percent= 4*16/116= it checks.
Notice how I checked it by working from the formula you proposed back to the original percents.
                    Answered by
            Chopsticks
            
    huh? so did i get my molecular forumla right? sorry im a bit confused on what you said.
    
                    Answered by
            bobpursley
            
    if it checks, it is right.
    
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