Question
Use the experimental molar mass to determine the molecular formula for compounds having the following analyses.
A.
41.39% carbon, 3.47% hydrogen, 55.14% Oxygen; experimental molar mass 116.07
I got C4H4O4 as the molecular formula.
Can someone check this for me?
A.
41.39% carbon, 3.47% hydrogen, 55.14% Oxygen; experimental molar mass 116.07
I got C4H4O4 as the molecular formula.
Can someone check this for me?
Answers
bobpursley
Assume 116.07grams (I didn't check that)
carbon percent= 4*12/116= check
O percent= 4*16/116= it checks.
Notice how I checked it by working from the formula you proposed back to the original percents.
carbon percent= 4*12/116= check
O percent= 4*16/116= it checks.
Notice how I checked it by working from the formula you proposed back to the original percents.
Chopsticks
huh? so did i get my molecular forumla right? sorry im a bit confused on what you said.
bobpursley
if it checks, it is right.