Asked by Cheyenne
What is the molar mass of 0.500 g of unknown monoprotic acid used in titration, if 22.5 mL of 0.15 M NaOH solution was required to neutralize it?
I do not need the answer, but instead an example of how to do a question just like it.
I do not need the answer, but instead an example of how to do a question just like it.
Answers
Answered by
bobpursley
moles base = .0225*.15
moles acid= mass/molmass
molmass= mass/moles acid= .5/(.0225*.15)
moles acid= mass/molmass
molmass= mass/moles acid= .5/(.0225*.15)
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.