Asked by Cheyenne

What is the molar mass of 0.500 g of unknown monoprotic acid used in titration, if 22.5 mL of 0.15 M NaOH solution was required to neutralize it?

I do not need the answer, but instead an example of how to do a question just like it.

Answers

Answered by bobpursley
moles base = .0225*.15
moles acid= mass/molmass

molmass= mass/moles acid= .5/(.0225*.15)
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