Asked by Lena
A -> 3C
The molar mass of A is 10.0g/mol
If 2.0 grams of A reacts, how many moles of C will be produced?
A -------------------> 3C
m.mass= 10.0g/mol
mass = 2.0 g
moles = 2.0 g/10.0 g/mol
=0.2 mol
moles of c = 3 x 0.2 = 0.6 mol
Did I do this correctly?
The molar mass of A is 10.0g/mol
If 2.0 grams of A reacts, how many moles of C will be produced?
A -------------------> 3C
m.mass= 10.0g/mol
mass = 2.0 g
moles = 2.0 g/10.0 g/mol
=0.2 mol
moles of c = 3 x 0.2 = 0.6 mol
Did I do this correctly?
Answers
Answered by
DrBob222
yes. or you can write it as
2.0 g A x (1 mole A/10.0 g A) x (3 moles C/1 mole A) = 0.6 mole C. Note that doing it this way, g A cancels with g A to give moles A, then moles A cancel with moles A and the only unit left is moles C which is what you wanted. The factors are arranged so that you cancel those units you don't want to keep and keep the unit required for the problem.
2.0 g A x (1 mole A/10.0 g A) x (3 moles C/1 mole A) = 0.6 mole C. Note that doing it this way, g A cancels with g A to give moles A, then moles A cancel with moles A and the only unit left is moles C which is what you wanted. The factors are arranged so that you cancel those units you don't want to keep and keep the unit required for the problem.
Answered by
Lena
Ohhh.. OK. I understand. Thank you soo much for all your help today :)
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