Question
HOW MANY GRAMS OF OCTANE WOULD BE NEEDED TO RELEASE 3,500 kJ OF HEAT?
2C8H18 + 25O2-----> 16CO2 + 18H2O
DeltaH= -5,530 kJ/mole of reaction
2C8H18 + 25O2-----> 16CO2 + 18H2O
DeltaH= -5,530 kJ/mole of reaction
Answers
bobpursley
one mole gives you 5530kj
so you want then 3500/5530 of one mole
mass then= 3500/5530 * molemass Octane
so you want then 3500/5530 of one mole
mass then= 3500/5530 * molemass Octane
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