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HOW MANY GRAMS OF OCTANE WOULD BE NEEDED TO RELEASE 3,500 kJ OF HEAT?

2C8H18 + 25O2-----> 16CO2 + 18H2O

DeltaH= -5,530 kJ/mole of reaction

1 answer

one mole gives you 5530kj
so you want then 3500/5530 of one mole
mass then= 3500/5530 * molemass Octane

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