Asked by Jo
Solve the quadratic equation 2x² - 4x + 1 = 0
How many solutions are in the equation 3x² + 4x - 7 = 0
How many solutions are in the equation 3x² + 4x - 7 = 0
Answers
Answered by
Anonymous
(a) use the quadratic formula
(b) the discriminant is positive, so two real roots
(b) the discriminant is positive, so two real roots
Answered by
Henry
1. 2x^2 - 4x + 1 = 0,
X = (-B +- sqrt(B^2-4AC))/2A,
X = (4 +- sqrt(16 - 8))/4 = 1.71, and 0.294.
2. 3x^2 + 4x - 7 = 0,
B^2 - 4AC = 16 + 84 = 100,
The discriminant is positive; therefore, we have 2 real solutions.
X = (-B +- sqrt(B^2-4AC))/2A,
X = (4 +- sqrt(16 - 8))/4 = 1.71, and 0.294.
2. 3x^2 + 4x - 7 = 0,
B^2 - 4AC = 16 + 84 = 100,
The discriminant is positive; therefore, we have 2 real solutions.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.