Asked by Summer
Ammonia (NH3) ionizes according to the following reaction:
NH3(aq)^+ H2O(l) ⇌ NH4^+(aq) + OH^–(aq)
The base dissociation constant for ammonia (NH3) is Kb = 1.8 × 10^–5. Ammonia (NH3) also has a chloride salt, ammonium chloride (NH4Cl), which is soluble in water.
If 0.070 M of ammonia (NH3) and 0.035 M of its salt ammonium chloride (NH4Cl) are mixed in a solution, what is the pH of this solution?
Answers
Answered by
DrBob222
A weak base and its salt is a buffer. Use the Henderson-Hasselbalch equation.
pH = pKa + log (base)/(acid)
Don't have pKa. You have Kb, convert to pKb, then pKa + pKb = pKw = 14 which will let you solve for pKa.
pH = pKa + log (base)/(acid)
Don't have pKa. You have Kb, convert to pKb, then pKa + pKb = pKw = 14 which will let you solve for pKa.
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