Question

A biker is slowing down according to the following table of velocities:


Time (secs) 0 1 2 3 4
Velocity (feet/sec) 25 20 16 12 10


Approximate the distance traveled, in feet, during these 4 seconds using 4 rectangles and a Left Riemann Sum.

A. 20.75
B. 58 <-----My choice
C. 73
D. 83


My work: s(4) = ∫04 v(t) dt ≈ [f(1) + f(2) + f(3) + f(4)]Δt = [20 + 16 + 12 + 10](1) = 58 feet.


AM i right? Thank you! :)

Answer 1

no, you used a right Riemann sum.

Answer 2

Oh ok. Got it

Answer 3

So it's 83?? s(0) = ∫04 v(t) dt ≈ [f(0) + f(1) + f(2) + f(3)+f(4)]Δt = [25 + 20 + 16 + 12 +10 ](1) = 83 feet.

Answer 4

that's better

Answer 5

It's 73
trust bro