Asked by Cassie

Acetic acid ionizes in water as follows:

CH3COOH + H2O --> CH3COO– + H3O+
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Fewer than 1% of ethanoic acid molecules are ionized at any instant. The acetate ion (CH3COO– ) is therefore ____.


A.a poor hydrogen-ion acceptor
B.a good hydrogen-ion acceptor
C.a poor hydrogen-ion donor
D.a good hydrogen-ion donor

I believe this is D?
Answered by Devron
A good hydrogen ion donor, I believe, would show more than 1% ionization. Therefore, CH3OOH is a weak acid, and a poor hydrogen-ion donor.
Answered by Cassie
ok...thank you