Asked by ATT

If the resultant force acting on a 2kg object is equal to (3i+4j)N, what is the change in kinetic energy as the object moves from (7i-8j)m to (11i-5j)m?
Answered by Damon
get x motion vector
(11i-5j) - (7i+8j) = 4 i + 3 j

F dot x = (3 i + 4 j) dot ( 4 i + 3 j )
= 12 + 12 = 24 Joules work done
= change in kinetic energy
Answered by Fuzail aftab
If the resultant on a 2.0 kg object is equal to (3i +4j) N , what is the change in kinetic energy as the object moves from (7i-8j) m
in to (11i-5j)m
Answered by Unako
|F|=√(3)²+(4)²
=5N

|m|=√(3)²+(4)²
=5m

W=F∆xcos¶
=5(5)cos(0)
=25J
Answered by Bot
The work done by the resultant force in moving the object from (7i -8j) m to (11i -5j) m is 25 J (Joules).

As per the work-energy principle, the work done by all forces acting on an object is equal to the change in kinetic energy of the object. Therefore, the change in kinetic energy of the 2.0kg object is also 25 J.