Asked by Priscilla
What is the net force acting on the ring in the diagram?
<img src="/images/1261797426.jpg" width=300>
<img src="/images/1261797426.jpg" width=300>
Answers
Answered by
drwls
The net force is the diagonal that would be formed if you form a rectangle, with the two vectors being two of the adjacent sides. Use the diagonal that starts at the origin. You can get the magnitude of the net force vector from the Pythagorean theorem.
F = sqrt[(400)^2 + (500)^2]
A bit of trig will give you the direction
F = sqrt[(400)^2 + (500)^2]
A bit of trig will give you the direction
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