Asked by marley
                a force f= 3i+cj+2k  acting on a particle causes displacement ,   d=-4i+2j+3k.
If the work done is 6 joule then the value of c.
Plz. Solve
            
        If the work done is 6 joule then the value of c.
Plz. Solve
Answers
                    Answered by
            drwls
            
    The dot product f*d equals 6 Joules, if the force is in Newtons and the displacement distance is in meters. 
-12 +2c +6 = 12
2c = 18
Take it from there
    
-12 +2c +6 = 12
2c = 18
Take it from there
                    Answered by
            Sidra
            
    (3i+cj+2k)(-4i+2j_3k)
= -12i+2cj-6k=6
=-12+2c-6=6
=-12+2c=6+6
=-12+2c=12
=2c=-12 -12
=2c =24
=c=24÷2
=c=12
Therefore, C=12.
    
= -12i+2cj-6k=6
=-12+2c-6=6
=-12+2c=6+6
=-12+2c=12
=2c=-12 -12
=2c =24
=c=24÷2
=c=12
Therefore, C=12.
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