Asked by Sarah
Calculate the standard entalphy of formation of naphthalene(C10H8) from the following data:
1) standard enthalphy of combustion of naphtalene is -5153kJ/mol
2) standard enthalphy of formation of CO2 is -393.5kJ/mol
3) standard enthalphy of formation of H2O is -285.8kJ/mol
1) standard enthalphy of combustion of naphtalene is -5153kJ/mol
2) standard enthalphy of formation of CO2 is -393.5kJ/mol
3) standard enthalphy of formation of H2O is -285.8kJ/mol
Answers
Answered by
DrBob222
C10H8 +12O2 ==>10CO2 + 4H2O
dHrxn = (n*dHo formation products) - (n*dHo formation reactants)
dHrxn = (n*dHo formation products) - (n*dHo formation reactants)
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