Question
3. Calculate the standard entropy change for the reaction:
N2 + 3H2 → 2NH3
given the standard entropies
Sº(N2)(g) = 191.6 J K^-1 mol^-1
Sº(H2)(g) = 130.6 J K^-1 mol^-1
Sº(NH3)(g) = 193.3 J K^-1 mol^-1
N2 + 3H2 → 2NH3
given the standard entropies
Sº(N2)(g) = 191.6 J K^-1 mol^-1
Sº(H2)(g) = 130.6 J K^-1 mol^-1
Sº(NH3)(g) = 193.3 J K^-1 mol^-1
Answers
DrBob222
dSrxn = (n*dSproducts) - (n*dSreactants)
olamide
192+3(131) >2(193.3)
192+393>386.6
585>386.6
585-386.6=198.4jkmol
192+393>386.6
585>386.6
585-386.6=198.4jkmol