Asked by Saira
Hi, i actually posted this up before..please double check the answers if i got them right have to hand in on Wednesday:
The Chemicals are:
Baking Soda- NaHC03
Calcium Chloride- CaCl2
Bromothymol Blue - (acid base indicator)
_______________________________________
What is:
(a) The equations for the dissolution of calcium chloride and sodium bicarbonate in water
1. CaCl2(s)---> Ca^2+(aq)+ 2Cl^-(aq)
2. NaHCO3(s) ---> Na+(aq) + HCO3^-(aq)
(b) Look up the heats of solutions for calcium chloride and sodium bicarbonate ( indicate exothermic and endothermic reaction)
Calcium choride
= -795.8 kJ mol^-1
= exothermic
Sodium bicarbonate
= -950.8 kJ mol^-1
= exothermic
(c)Look up the solubilities of these two salts and any other salts that may form, in put in a Ziploc bag.
Solubilities in water:
CaCl2- 74.5 g/ 100ml ( 20C)
NaHCO3- 7.8 g/ 100ml (18C)
other salts that may form are:
1.NaCl- 35.9 g/ 100ml (25C)
2.Ca(OH)2- 0.185g/ 100 cm3
3.Ca(HCO3)2- 16.6 g/100ml ( 20C)
4.CaCO3- 0.00015 mol/l (25C)
And CO2 will form after the bicarbonate breaks down : 0.00145g/ml ( 25C)
(d)Write out the equations for the neutralization of a strong acid with a strong base.
1. HCl(aq)+NaOH(aq)---> NaCl(aq)+H20(l)
2. 2HBr(aq)+Ba(OH)2(aq)-->BaBr2(aq)+2H2O
3. HI (aq)+ NaOH--> NaI(aq) + H2O
4. 2HClO4+Sr(OH)2--> Sr(ClO4)2+ 2H20
(e)Write out the Ka and Kb for the biocarbonate ion with chemical equation
HCO3^-(aq) <--> H+(aq) + CO3^-2(aq)
Ka = [H+][CO3-2]/[HCO3-
H2O + CO3-2(aq) <--> HCO3-(aq) + OH-(aq)
Kb = [HCO3-][OH-]/[CO3-2]
(F) the pH range for the indicator bromothymol blue
The pH range for bromothymol blue is
= Y 6.0 - 7.0 B
The Chemicals are:
Baking Soda- NaHC03
Calcium Chloride- CaCl2
Bromothymol Blue - (acid base indicator)
_______________________________________
What is:
(a) The equations for the dissolution of calcium chloride and sodium bicarbonate in water
1. CaCl2(s)---> Ca^2+(aq)+ 2Cl^-(aq)
2. NaHCO3(s) ---> Na+(aq) + HCO3^-(aq)
(b) Look up the heats of solutions for calcium chloride and sodium bicarbonate ( indicate exothermic and endothermic reaction)
Calcium choride
= -795.8 kJ mol^-1
= exothermic
Sodium bicarbonate
= -950.8 kJ mol^-1
= exothermic
(c)Look up the solubilities of these two salts and any other salts that may form, in put in a Ziploc bag.
Solubilities in water:
CaCl2- 74.5 g/ 100ml ( 20C)
NaHCO3- 7.8 g/ 100ml (18C)
other salts that may form are:
1.NaCl- 35.9 g/ 100ml (25C)
2.Ca(OH)2- 0.185g/ 100 cm3
3.Ca(HCO3)2- 16.6 g/100ml ( 20C)
4.CaCO3- 0.00015 mol/l (25C)
And CO2 will form after the bicarbonate breaks down : 0.00145g/ml ( 25C)
(d)Write out the equations for the neutralization of a strong acid with a strong base.
1. HCl(aq)+NaOH(aq)---> NaCl(aq)+H20(l)
2. 2HBr(aq)+Ba(OH)2(aq)-->BaBr2(aq)+2H2O
3. HI (aq)+ NaOH--> NaI(aq) + H2O
4. 2HClO4+Sr(OH)2--> Sr(ClO4)2+ 2H20
(e)Write out the Ka and Kb for the biocarbonate ion with chemical equation
HCO3^-(aq) <--> H+(aq) + CO3^-2(aq)
Ka = [H+][CO3-2]/[HCO3-
H2O + CO3-2(aq) <--> HCO3-(aq) + OH-(aq)
Kb = [HCO3-][OH-]/[CO3-2]
(F) the pH range for the indicator bromothymol blue
The pH range for bromothymol blue is
= Y 6.0 - 7.0 B
Answers
Answered by
Chris
It looks right, but I can't be sure if you're entirely correct.
Did you use your textbook to find these values?
Did you use your textbook to find these values?
Answered by
Saira
The solubilities of the of the compunds i found on the internet the rest from the textbook.
Answered by
Senzation
I love you man
Answered by
eric
hey if u guys are still around, i think e is wrong. check general chem text book pg 682 table 16.4 it shows u the Ka equation for bicarbonate and even the ka value
Answered by
Sarah
Hey! thanks so much! Love you!