Question
In the titration of Na2S2O3 against KIO3 the average titre value was 23.1cm3,the volume of iodine used in the titration was 25cm3 and the concentration of Na2S2O3 was 0.1M.calculate the molarity of KIO3
Answers
2.34 moles
Writeacher
And why should Sarah believe the answer that andrew threw out there? He explained nothing.
bobpursley
Na2S2O3 + 2 KIO3 = K2S2O3 + 2 NaIO3
So,
molesKIO3=1/2 molesNa2S2O3
M*.025=.5*.1*.0231
M=??
So,
molesKIO3=1/2 molesNa2S2O3
M*.025=.5*.1*.0231
M=??
bobpursley
and if course, Sarah knows what Andrew posted cannot possibly be correct.
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