Asked by TNT

An Earth satellite moves in a circular orbit 616 km above the Earth's surface. The period of the motion is 96.8min.
(a) What is the speed of the satellite?
(b) What is the magnitude of the centripetal acceleration of the satellite
Answered by Scott
Earth radius is 6371 km ... google

orbit radius ... 6371 + 616

circumference ... 2 π r

(a) speed = circumference / period

(b) a = speed^2 / r
Answered by bobpursley
the distance around once is 2PI*(radEarth+6.16e8m)
velocity then= distance/period
make certain distance is in meters, and period is in seconds.

b. what is v^2/r ?
Answered by TNT
very helpful information. I need a teacher like you.
There are no AI answers yet. The ability to request AI answers is coming soon!