Asked by Kelsey

A satellite moves in a circular orbit around Earth at a speed of 4390 m/s
(a) Determine the satellite's altitude above the surface of Earth.(meters)


(b) Determine the period of the satellite's orbit.
(hours)

I used the equation M(sattelite)V^2/r = M(sattelite)(Mass(earth)G/r^2

and tried to solve for r by canceling out one r and the M(sattelite) which gave me


r = GM(earth)/v^2


the answer i keep getting is 20,592,718.12m

but it is not right....
Answered by drwls
Have you tried subtracting the radius of the Earth? They asked for the altitude. "r" is the distance from the center of the Earth.
Answered by Kelsey
oh wow, thanks....

wish I would have thought of that.


it worked.
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