10 cm = 0.10 meter
so r from each = 0.05
the fields have the same r but add because one is + and the other - and they are in opposite directions so just add charges
Q = (8.8+5.4)*10^-6 coulombs
E = k Q/(0.05)^2
What is the magnitude of the electric field at a point midway between a −8.3μC and a +5.4μC charge 10cm apart? Assume no other charges are nearby.
2 answers
like if ur with me
1 answer