Asked by Anonymous
What is the magnitude of the net electrostatic force a Boron nucleus would experience at the point halfway between the Magnesium nucleus and the 3e charge on the y axis in N?
Answers
Answered by
Anonymous
it depends on how far apart the two charges are.
Answered by
Anonymous
q*E=F
Answered by
Elena
q₁ = 3 e,
q₂ = 12e,
q₃ = 5e
The electric field at the midpoint is
E= kq₂/(x/2)²- kq₁/(x/2)²=
=k(12e-3e)/(x/2)² =k36e/x² (directed to the 3e charge)
F= q₃E=k36e•5e/x²=
=k•180e/x²,
where
k =9•10⁹ N•m²/C²,
e =1.6•10⁻¹⁹ C,
x is the distance between 3e and 12e
q₂ = 12e,
q₃ = 5e
The electric field at the midpoint is
E= kq₂/(x/2)²- kq₁/(x/2)²=
=k(12e-3e)/(x/2)² =k36e/x² (directed to the 3e charge)
F= q₃E=k36e•5e/x²=
=k•180e/x²,
where
k =9•10⁹ N•m²/C²,
e =1.6•10⁻¹⁹ C,
x is the distance between 3e and 12e
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