Asked by Aspen

The length of a rectangular room is two feet less than three times its width. The area of the
rectangle is 176 square feet.

a) Write an algebraic equation to model this problem.
b) Solve the equation to find the dimensions of the rectangle.
Answered by Arora
Length = x
Width = y

a) x = 3y - 2

b) Area = Length*Width
= xy
=(3y-2)(y)

=> 176 = 3y^2 - 2y

Solve the quadratic for the dimensions.
Answered by Aspen
How do I find x? I found y as y= 8, -22/3 but should I calculate x with the two solutions of y?
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