Question

The length of a rectangular room is two feet less than three times its width. The area of the
rectangle is 176 square feet.

a) Write an algebraic equation to model this problem.
b) Solve the equation to find the dimensions of the rectangle.
Length = x
Width = y

a) x = 3y - 2

b) Area = Length*Width
= xy
=(3y-2)(y)

=> 176 = 3y^2 - 2y

Solve the quadratic for the dimensions.
How do I find x? I found y as y= 8, -22/3 but should I calculate x with the two solutions of y?

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