Asked by Hal
The length of Joe's rectangular garden is 1 meter less than twice its width, and its area is 120m^2. Find the dimensions of the garden by setting up a quadratic equation and define its variables.
Answers
Answered by
Kuai
A = l*w
l = 2w -1
120 = (2w-1)w
120 = 2w^2 -w
2w^2 -w -120 = 0
l = 2w -1
120 = (2w-1)w
120 = 2w^2 -w
2w^2 -w -120 = 0
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