Asked by crystal
explain why (x + y)2= x2 + y2
Answers
Answered by
Damon
If you are telling me that
(x+y)^2 = x^2 + y^2
That is not true
(x+y)^2 = x^2 + 2 x y + y^2
as you can see by multiplying
(x+y)(x+y) = x(x+y) + y(x+y) =x^2 + xy + xy + y^2
(x+y)^2 = x^2 + y^2
That is not true
(x+y)^2 = x^2 + 2 x y + y^2
as you can see by multiplying
(x+y)(x+y) = x(x+y) + y(x+y) =x^2 + xy + xy + y^2
Answered by
Damon
Now if you mean
2 (x + y) = 2 x + 2 y
that is simply the distributive property of multipication.
2 (x + y) = 2 x + 2 y
that is simply the distributive property of multipication.
Answered by
john
solc for v
[\sqrt;[6v-2]]=[\sqrt;[9v-8]]
[\sqrt;[6v-2]]=[\sqrt;[9v-8]]
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