Question
you want to make a 0.5 m acetate buffer at a ph = 5.5. how much acetic acid and base should you mix
Answers
DrBob222
Do you mean 0.5 m or 0.5M. I see you don't seem to know there is a caps key on the keyboard. There is and I suggest you find it. m means molality and M means molarity. I assume you meant M. The next assumption is what volume do you want. Let's say 1000 mL.
pH = pKa + log (Ac^-)/(HAc)
Look up pKa, substitute into the equation, and solve for the ratio of (Ac^-)/(HAc). That is equation 1.
Eqquation 2 is HAc + Ac^- = 0.5.
Solve the two equation simultaneously for (HAc) and (.5)
Now, knowing (HAc) and (Ac^-) and that you want a liter of solution, calculate grams HAc and Ac^-.
Post your work if you get stuck.
pH = pKa + log (Ac^-)/(HAc)
Look up pKa, substitute into the equation, and solve for the ratio of (Ac^-)/(HAc). That is equation 1.
Eqquation 2 is HAc + Ac^- = 0.5.
Solve the two equation simultaneously for (HAc) and (.5)
Now, knowing (HAc) and (Ac^-) and that you want a liter of solution, calculate grams HAc and Ac^-.
Post your work if you get stuck.
DrBob222
Your prof PROBABLY wants you to add NaOH to HAc to prepare but you didn't show molarity of acids or bases available so I didn't do it that way.