Use the HH equation and solve for Ac.
pH = pKa + log (Ac/HAc)
5.027 = 4.744 + log Ac/0.5
Now convert M Ac to grams.
How many moles of sodium acetate
(NaCH3COO) must be added to 1.000 liter of a 0.500M solution of acetic acid (CH3COOH) to produce a pH of 5.027? The ionization constant of acetic acid is 1.8 × 10−5.
Answer in units of mol
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