Asked by Kay
If the pressure of the gas inside the flask were increased and the height of the column in the open-ended arm went up by 0.5mm, what would be the new pressure of the gas in the flask, in torr?
ANSWER IS 807.3 TORR
ANSWER IS 807.3 TORR
Answers
Answered by
DrBob222
I don't believe you have enough information.
Answered by
hanna
This question [is a sample problem in Section 10.2 of the Beer, et. al. Chemistry text book and] is a follow up to the one asked and answered here:
tinyurl.com/sj4aaqt
Initial conditions needed to solve this question:
P_atmo = 764.7 torr
h_atmo = 136.4 mm (of Hg)
h_gas = 103.8 mm (of Hg)
Calculate the new heights:
h_atmo2 = h_atmo + 5.0 mm = 141.4 mm
h_gas2 = h_gas - 5.0 mm = 98.8 mm
Then plug and chug:
P_gas2 = P_atmo + (h_atmo2 - h_gas2)
= 764.7 + (141.4 - 98.8)
= 807.3 torr
tinyurl.com/sj4aaqt
Initial conditions needed to solve this question:
P_atmo = 764.7 torr
h_atmo = 136.4 mm (of Hg)
h_gas = 103.8 mm (of Hg)
Calculate the new heights:
h_atmo2 = h_atmo + 5.0 mm = 141.4 mm
h_gas2 = h_gas - 5.0 mm = 98.8 mm
Then plug and chug:
P_gas2 = P_atmo + (h_atmo2 - h_gas2)
= 764.7 + (141.4 - 98.8)
= 807.3 torr
Answered by
hanna
Correction: Brown, et. al. text book.
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