Asked by Heather

At takeoff a commercial jet has a 45.0 m/s speed. Its tires have a diameter of 0.850 m.
(a) At how many rpm are the tires rotating?


Incorrect: Your answer is incorrect.
rpm
(b) What is the centripetal acceleration at the edge of the tire?

4764.70

Correct: Your answer is correct.
m/s2
(c) With what force must a determined 10-15 kg bacterium cling to the rim?

N
(d) Take the ratio of this force to the bacterium's weight.

(force from part (c) / bacterium's weight)
Answered by Henry
a. Circumference = pi*D = 3.14 * 0.85 = 2.67 m.

1rev/2.67m * 45m/s * 60s/min = 1012 rev/min.

Answered by lil pump
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Answered by Travis Scott
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Answered by Offset
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Answered by Takeoff
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