Asked by EMMANUEL OLA 1
A body accelerates from rest at 0.2m/s for one-fifth of a minute.Calculate the distance covered by the body.
Answers
Answered by
bobpursley
d=1/2 a t^2=1/2 *.2 m/s^2 *12^2 s^2
d=14.4 m
d=14.4 m
Answered by
Damon
I think you might mean 0.2 m/s^2
d = (1/2) a t^2
a = 0.2 m/s^2
t = 60/5 = 12 seconds
d = (1/2)(.2)(144) = 14.4 meters
d = (1/2) a t^2
a = 0.2 m/s^2
t = 60/5 = 12 seconds
d = (1/2)(.2)(144) = 14.4 meters
Answered by
ibukun
can't you solve the question clearly.
Answered by
ibukun
Damon not one-fifth but 20seconds so solve again
Answered by
Adeyemi timon
Use this formula (s=ut+1/2at2)
That will give us 14.4m
That will give us 14.4m
Answered by
Beamer
That will give us 14.4m
Answered by
Moketsib
A car accelerates at 2 m /s from rest for two minutes calculate the displacement after two minutes
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