Asked by Anonymous
Box A contains six white marbles and five black marbles. Box B contains three white marbles and four black marbles. An experiment consists of first selecting a marble at random from Box A. The marble is transferred to Box B and then a second marble is drawn from Box B. What is the probability that the first marble was white given that the second marble was white?
Answers
Answered by
Reiny
We have four possible outcomes:
1 ww **
2 wb
3 bw
4 bb
we want the cases marked by **
#1:
ww, prob(first w) = 6/11
so the white gets transferred to B and
prob(2nd w) = 4/8 = 1/2
prob(ww) = (6/11)(1/2) = 6/22 = 3/11
1 ww **
2 wb
3 bw
4 bb
we want the cases marked by **
#1:
ww, prob(first w) = 6/11
so the white gets transferred to B and
prob(2nd w) = 4/8 = 1/2
prob(ww) = (6/11)(1/2) = 6/22 = 3/11
Answered by
Steve
well,
P(BW) = 5/11 * 3/8
P(WW) = 6/11 * 4/8
so, what does hat tell you?
P(BW) = 5/11 * 3/8
P(WW) = 6/11 * 4/8
so, what does hat tell you?