Duplicate Question
The question on this page has been marked as a duplicate question.
Original Question
An ideal gas is sealed within a container at a tempreture of 17 degree celcies and a pressure of 101KPa. The container is heate...Asked by Aboodi
An Ideal gas is sealed within a container at a temperature of 17 degree Celsius and a pressure of 101 KPa. The container is heated until temperature of the gas reaches 100 degree Celsius. A valve in the container is then opened to allow gas to escape until the pressure falls back to 101KPa at 100 degree Celsius.
a) Calculate the pressure in the gas just before the valve is opened.
b) Calculate the fraction of the initial mass of gas that was lost as a result of opening the valve.
a) Calculate the pressure in the gas just before the valve is opened.
b) Calculate the fraction of the initial mass of gas that was lost as a result of opening the valve.
Answers
Answered by
Damon
Ti = initial temp = 273+17
Tf = final temp = 273 + 100
initial Pi = 101,000 Pa
final Pf = ? before valve opened
before opening:
P V/nT = R
Pi V/n Ti = Pf V/n Tf
or in other words
Pi/Ti = Pf/Tf
Pf = Pi Tf/Ti
after opening n changes
ni = Pi V/RTi
nf = Pi V/RTf
nf/ni = Ti/Tf
It says fraction lost so 1 - Ti/Tf
Tf = final temp = 273 + 100
initial Pi = 101,000 Pa
final Pf = ? before valve opened
before opening:
P V/nT = R
Pi V/n Ti = Pf V/n Tf
or in other words
Pi/Ti = Pf/Tf
Pf = Pi Tf/Ti
after opening n changes
ni = Pi V/RTi
nf = Pi V/RTf
nf/ni = Ti/Tf
It says fraction lost so 1 - Ti/Tf
Answered by
Aboodi
Damon can you write b in more detail ?
Answered by
abinezer
12
Answered by
Ze
Why the temprature and the volume is constant
Answered by
abdujabar
physics
Answered by
abdujabar
1.A and B
Answered by
israel
pf=129.9 kpa or 129.9 * 10^3 pa
There are no AI answers yet. The ability to request AI answers is coming soon!