Asked by phyllis
a tank of ideal gas is sealed off at 20 degrees C and 1.00 atm pressure. What will be the pressure (in kPa and mmHg) in the tank if the gas temperature is decreased to -35degrees C ?
the book answer is
82kPa = 6.2 x10^2 mmHg
can you help me figure out how the book got this answer.
I've tried to plug the numbers into the gas formulas and have not had any luck.
the book answer is
82kPa = 6.2 x10^2 mmHg
can you help me figure out how the book got this answer.
I've tried to plug the numbers into the gas formulas and have not had any luck.
Answers
Answered by
drwls
At constant V and number of moles, P is proportional to absolute T.
P2/P1 = T2/T1 = 238/293 = 0.8123
P2 = 760 mm Hg * 0.8123 = 617 mm Hg
rRound it off to 620.
You have to know that 7600 mm Hg = 1 atmosphere, and how to convert degrees C to K
P2/P1 = T2/T1 = 238/293 = 0.8123
P2 = 760 mm Hg * 0.8123 = 617 mm Hg
rRound it off to 620.
You have to know that 7600 mm Hg = 1 atmosphere, and how to convert degrees C to K
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